Question

Three unbiased coins are tossed. What is the probability of getting at most one head?

• A. 1/2
• B. 1/4
• C. 1/9
• D. 3/8
• E. None of these

Answer 1

The correct option is A

1/2

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT}.

$\therefore$ P(E) = $\frac{4}{8}=\frac{1}{2}$.