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Question

Three uniform rods, each of mass M and length l, are connected to form an equilateral triangle in a gravity free space. Another small body of mass m is kept at the centroid. Find the minimum velocity v to be given to mass m so that it escapes the gravitational pull of the triangle.

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Solution

The gravitational potential energy between the point mass m and the elementary segment is given as
dU=Gm(dm)r=Gm{(Ml)dx}/a2+x2
=GMmldxa2+x2
The total gravitational potential energy associated with the system, U=3dU
=(3GMml)2l/20dxa2+x2
=6GMml[lnxa+a2+x2a]l/20
U=6GMmlln∣ ∣l/2+a2(l/2)2a∣ ∣
U=6GMmllnl+l2+4a22a
For minimum velocity |U|=12mv2
v=[12GMl.lnl+l2+4a22a]1/2 Put, a=l3sin60=l23
v=[12GMl.ln(2+3)]1/2.
932779_1013602_ans_9213d4ffe03645c0a32ecb32ea4ba047.jpg

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