Question

# Three vectors $$\vec { A } =a\vec { i } +\vec { j } +\vec { k } ,\vec { B } =\vec { i } +b\vec { j } +\vec { k } ,\vec { C } =\vec { i } +\vec { j } +c\vec { k }$$ are mutually perpendicular ($$\vec { i } ,\vec { j } ,\vec { k }$$ are unit vectors along $$X,Y,Z$$ axis respectively). The respective values of $$a,b$$ and $$c$$ are

A
0,0,0
B
12,12,12
C
1,1,1
D
12,12,12

Solution

## The correct option is B $$-\cfrac { 1 }{ 2 } , -\cfrac { 1 }{ 2 } , -\cfrac { 1 }{ 2 }$$$$a+b+1=0$$  ------- (1)$$1+b+c=0$$  --------(2)$$a+1+c=0$$  ---------(3)--------------------$$2(a+b+c)+3=0$$$$a+b+c=-\cfrac{3}{2}$$  ---- (4)$$\Rightarrow$$ $$-1+c=\cfrac{-3}{2}$$ using (1)$$c=-\dfrac{1}{2}$$    $$b= - \dfrac{1}{2}$$       $$a= -\dfrac{1}{2}$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More