Three vectors A- B- and C- are related as A-B-C- If C- is perpendicular to A- and the -C- is equal to the -A- what will be the angle between A and B -A- 45-B- 90-C- 180-D- 135-

The correct option is A Since A⃗ + B⃗ = C⃗, C⃗ is the resultant of A⃗ and B⃗ Using the triangle law of vector addition (see figure), we have θ = 45^∘ because ...

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Byju's Answer

Standard XII

Physics

Vector Addition

Three vectors...

Question

Three vectors $\to A, \to B a n d \to C$ are related as $\to A + \to B = \to C$ . If $\to C$ is perpendicular to $\to A$ and the $| \to C |$ is equal to the $| \to A |$ , what will be the angle between $\to A a n d \to B$ ?

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Solution

The correct option is A
Since $\to A + \to B = \to C$ , $\to C$ is the resultant of $\to A a n d \to B$
Using the triangle law of vector addition (see figure),

we have $θ = 45^{\circ} b e c a u s e | \to A | = | \to C |$
Thus the correct choice is (a).

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Similar questions

Q. Three vectors

\to A, \to B a n d \to C

are related as

\to A + \to B = \to C

. If

\to C

is perpendicular to

\to A

and the

| \to C |

is equal to the

| \to A |

, what will be the angle between

\to A a n d \to B

Q. Let

\to a, \to b

and

\to c

be three vectors such that

| \to a | = \sqrt{3}, | \to b | = 5, \to b . \to c = 10

and the angle between

\to b

and

\to c

\frac{π}{3} .

\to a

is perpendicular to vector

\to b \times \to c

, then

| \to a \times (\to b \times \to c) |

is equal to

Q. If

\to a, \to b

and

\to c

are perpendicular to

\to b + \to c, \to c + \to a

and

\to a + \to b

respectively and if

| \to a + \to b | = 6, | \to b + \to c | = 8

and

| \to c + \to a | = 10

, the

| \to a + \to b + \to c |

is equal to

Q. The length of the perpendicular from the origin to the plane passing through three non-collinear points

\to a, \to b, \to c

Q. For any three vectors

\to a, \to b, \to c

\to a \times (\to b + \to c) + \to b \times (\to c + \to a) + \to c \times (\to a + \to b)

equals to

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Three vectors →A,→B and →C are related as →A+→B=→C. If →C is perpendicular to →A and the |→C| is equal to the |→A|, what will be the angle between →A and →B?

The correct option is A Since →A+→B=→C, →C is the resultant of →A and →B Using the triangle law of vector addition (see figure), we have θ=45∘ because |→A|=|→C| Thus the correct choice is (a).

Three vectors $\to A, \to B a n d \to C$ are related as $\to A + \to B = \to C$ . If $\to C$ is perpendicular to $\to A$ and the $| \to C |$ is equal to the $| \to A |$ , what will be the angle between $\to A a n d \to B$ ?

The correct option is A
Since $\to A + \to B = \to C$ , $\to C$ is the resultant of $\to A a n d \to B$
Using the triangle law of vector addition (see figure),

we have $θ = 45^{\circ} b e c a u s e | \to A | = | \to C |$
Thus the correct choice is (a).