Three vectors →A,→B and →C satisfy the relation →A⋅→B=0 and →A⋅→C=0. The vector A is parallel to :
A
→B.→C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
→B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
→C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
→B×→C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D→B×→C →A is perpendicular to →B and →A is perpendicular to →C. Thus →A must lie along the direction of the cross product of →B and →C. Alternatively: Given, →A.→B=0 →A.→C=0 ⇒→A.→B−→A.→C=→A(→B−→C)=0 ⇒→A⊥(→B−→C) ⇒→A∥(→B×→C)