Three waves of amplitudes 12μm, 4μm and 9μm but of same frequency arrive at a point in a medium with a successive phase diffeerence of π2. Then the resultant amplitude is
A
4
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B
7
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C
5
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D
25
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Solution
The correct option is C5 Since three waves have a successive phase difference of π/2. So, first and third waves have phase difference of π. Thus, net amplitude of first and third wave is A1=12−9=3μm Amplitude of second wave A2=4μm Resultant amplitude AR=√A21+A22 ∴AR=√32+42=5μm