Three years ago, the population of a town was $50000$ . If the annual increase during three successive years be at the rate of $5$ %, $4$ % and $3$ % respectively. What is the present population?

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Solution

Population of town $3$ years ago $= 50000$

Annual percentage increase in $3$ years $= 5 %, 4 %, 3 %$ .resp.

$∴$ Present population $= 50, 000 (1 + \frac{A_{1}}{100}) (1 + \frac{A_{2}}{100}) (1 + \frac{A_{3}}{100})$

$= 5000 (1 + \frac{5}{100}) (1 + \frac{4}{100}) (1 + \frac{3}{100})$

$= 5000 \times \frac{105}{100} \times \frac{104}{100} \times \frac{103}{100}$

Present population $= 56238 R s$

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Three years ago, the population of a town was 50000. If the annual increase during three successive years be at the rate of 5%, 4% and 3% respectively. What is the present population?

Population of town 3 years ago =50000Annual percentage increase in 3 years =5%,4%,3%.resp.∴ Present population =50,000(1+A1100)(1+A2100)(1+A3100)=5000(1+5100)(1+4100)(1+3100)=5000×105100×104100×103100 Present population =56238Rs

Three years ago, the population of a town was $50000$ . If the annual increase during three successive years be at the rate of $5$ %, $4$ % and $3$ % respectively. What is the present population?