You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Activation Energy

Threshold fre...

Question

Threshold frequency of metal is $f_{0}$ . When light of frequency $θ$ = $2 f_{0}$ is incident on the metal plate, velocity of electron emitted in $V_{1}$ . When a frequency of incident radiation is $5 f_{0} . V_{2}$ is velocity of emitted electron, then $V_{1} : V_{2}$ is

1 : 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
1 : 2

$h v = \frac{1}{2} m v_{1}^{2}$

$v_{1}^{2} = \frac{2 h v}{m}$

$v_{1} = \sqrt{\frac{2 h v}{m}}$

$v_{2} = \sqrt{\frac{8 h v}{m}}$

$v_{1} : v_{2}$

$\sqrt{\frac{2 h v}{m}} : \sqrt{\frac{8 h v}{m}}$

$1 : 2$

Suggest Corrections

Similar questions

Q. Threshold frequency of a metal is

f_{0}

. when light of frequency

v = 2 f_{0}

is incident on the metal plate, the maximum velocity of the electron that is emitted is

v_{1}

. When the frequency of incident radiation is

5 f_{0}

, and the maximum velocity of the emitted electron is

v_{2}

, find the ratio

\frac{v_{1}}{v_{2}}

Q. Threshold frequency of a metal is

f_{0}

. when light of frequency

v = 2 f_{0}

is incident on the metal plate, the maximum velocity of the electron that is emitted is

v_{1}

. When the frequency of incident radiation is

5 f_{0}

, and the maximum velocity of the emitted electron is

v_{2}

, find the ratio

\frac{v_{1}}{v_{2}}

Q. When the light of frequency

2 ν_{0}

(where

ν_{0}

is a threshold frequency) is incident on a metal plate, the maximum velocity of electrons emitted is

v_{1}

. When the frequency of the incident radiation is increased to

5 ν_{0}

, the maximum velocity of electrons emitted from the same plate is

v_{2}

. The ratio of

v_{1}

v_{2}

Q. When the light of frequency

2 v_{0}

(where

v_{0}

is threshold frequency), is incident on a metal plate, the maximum velocity of electrons emitted is

v_{1}

. When the frequency of the incident radiation is increased to

5 v_{0}

, the maximum velocity of electrons emitted from the same plate is

v_{2}

. The ratio of

v_{1}

v_{2}

is?

Q. When the light of frequency

2 ν_{0}

(where

ν_{0}

is a threshold frequency) is incident on a metal plate, the maximum velocity of electrons emitted is

v_{1}

. When the frequency of the incident radiation is increased to

5 ν_{0}

, the maximum velocity of electrons emitted from the same plate is

v_{2}

. The ratio of

v_{1}

v_{2}

Join BYJU'S Learning Program

Threshold frequency of metal is f0. When light of frequency θ = 2 f0 is incident on the metal plate, velocity of electron emitted in V1. When a frequency of incident radiation is 5 f0.V2 is velocity of emitted electron, then V1 : V2 is

The correct option is B 1 : 2 hv = 12mv21 v21 = 2hvm v1 = √2hvm v2 = √8hvm v1 : v2 √2hvm : √8hvm 1 : 2

Threshold frequency of metal is $f_{0}$ . When light of frequency $θ$ = $2 f_{0}$ is incident on the metal plate, velocity of electron emitted in $V_{1}$ . When a frequency of incident radiation is $5 f_{0} . V_{2}$ is velocity of emitted electron, then $V_{1} : V_{2}$ is

The correct option is B
1 : 2

$h v = \frac{1}{2} m v_{1}^{2}$

$v_{1}^{2} = \frac{2 h v}{m}$

$v_{1} = \sqrt{\frac{2 h v}{m}}$

$v_{2} = \sqrt{\frac{8 h v}{m}}$

$v_{1} : v_{2}$

$\sqrt{\frac{2 h v}{m}} : \sqrt{\frac{8 h v}{m}}$

$1 : 2$