Question

Question 97

Thrice a number decreased by 5 exceeds twice the number by 1. Find the number.

Answer 1

Let the number be x. Then, thrice of this number = 3x and twice of this number = 2x.
If we decrease thrice of x by 5, we get (3x - 5).
According to the question,
(3x - 5) - (2x) = 1
$\Rightarrow 3x-5-2x=1\Rightarrow x-5=1\Rightarrow x=1+5\left[transposing\right(-5\left)toRHS\right]\Rightarrow x=6$
Hence, the required number is 6.