Question

Through a narrow aperture, diffusion of 2 liters of $H_2$ takes place in 2 hours. Under the same conditions, time required in hours for the diffusion of 1 liter of oxygen is:

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (D)

4

$\frac{r_A}{r_B}=\frac{V_1/t_1}{V_2/t_2}$

$=\sqrt{\frac{M_B}{M_A}}$

Here, $V_1=2litres,V_2=1litres,t_1=2hours$

Molecular weight of dioxygen is 32 and that of dihydrogen is 2.
$\frac{r_A}{r_B}$

$=\frac{1}{1/t_2}$

$=\sqrt{\frac{32}{2}}$

$=4$