Through a rectangular field of length, $90 m$ and breadth $60 m$ two roads are constructed which are parallel to the sides and cut each other right angles through the center of the fields. If the width of each road is $3 m$ , find the area converted by the roads.

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Solution

R.E.F. Image.
Given the length of field $= 90 m$
width of field $= 60 m .$
Area of field $= 90 \times 60$
Area $= 5400 m^{2}$
length of road GEFH $= 90 m .$
length of road ABCD $= 60 m .$
width of each road $= 3 m$ [Given].

Area of roads $= a r (A B C D) + a r . (G E F H) - a r (L I J K)$

$= 90 \times 3 + 60 \times 3 - 3 \times 3$

$= 270 + 180 - 9$

Area of roads $= 441 m^{2} .$

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Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the center of the fields. If the width of each road is 3 m, find:

The area covered by the roads

Q. Through a rectangular field of length

90 m

and breadth

60 m

two roads are constructed which are parallel to the sides and cut each other right angles through the centre of the fields. If the width of each road is

3 m

, find the cost of constructing the roads at the rate of

R s . 110

per

m^{2}

Question 7 (ii)

Q. Through a rectangular field of sides 90 m × 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the field. If the which of the road is 3 m, find the total area cobered by the two roads.

Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3 m, find

(i) the area covered by the roads.

(ii)the cost of constructing the roads at the rate of Rs 110 per m².

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Through a rectangular field of length, 90 m and breadth 60 m two roads are constructed which are parallel to the sides and cut each other right angles through the center of the fields. If the width of each road is 3 m, find the area converted by the roads.

R.E.F. Image.Given the length of field =90mwidth of field =60m.Area of field =90×60Area =5400m2length of road GEFH =90m.length of road ABCD =60m.width of each road =3m [Given].Area of roads =ar(ABCD)+ar.(GEFH)−ar(LIJK)=90×3+60×3−3×3=270+180−9Area of roads =441m2.

Through a rectangular field of length, $90 m$ and breadth $60 m$ two roads are constructed which are parallel to the sides and cut each other right angles through the center of the fields. If the width of each road is $3 m$ , find the area converted by the roads.