Through the vertex A of A B C- a line X Y is drawn parallel to B C-

The correct option is C a+b+c = x+a+y a+b+c=180^∘…(1) [Sum of angles in a triangle] Also, x+a+y=180^∘…(2) [Angles on a straight line] ∴ From (1) an ...

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Standard IX

Mathematics

Given Perimeter and Two Base Angles

Through the v...

Question

Through the vertex A of $Δ$ ABC, a line XY is drawn parallel to BC.

Which of the following is correct?

b = y

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c = x

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a = b

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a+b+c = x+a+y

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Solution

The correct option is D
a+b+c = x+a+y

$a + b + c = 180^{\circ} \dots (1) [Sum of angles in a triangle]$
Also, $x + a + y = 180^{\circ} \dots (2) [Angles on a straight line]$
$∴$ From (1) and (2),
a + b + c = x + a + y

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Through the vertex A of ΔABC, a line XY is drawn parallel to BC. Which of the following is correct?

The correct option is D a+b+c = x+a+y a+b+c=180∘…(1) [Sum of angles in a triangle] Also, x+a+y=180∘…(2) [Angles on a straight line] ∴ From (1) and (2), a + b + c = x + a + y

Through the vertex A of $Δ$ ABC, a line XY is drawn parallel to BC.

Which of the following is correct?

The correct option is D
a+b+c = x+a+y

$a + b + c = 180^{\circ} \dots (1) [Sum of angles in a triangle]$
Also, $x + a + y = 180^{\circ} \dots (2) [Angles on a straight line]$
$∴$ From (1) and (2),
a + b + c = x + a + y