Through which side of a vehicle should a driver overtake?
On one way traffic road, the speeds of overtaking and overtaken vehicles are 80 kmph and 50 kmph respectively. If the acceleration of the overtaking vehicle is 2.5 kmph per second, calculate the overtaking sight distance (Assume spacing between vehicles is 16 m, reaction time of driver is 2 seconds)
The acceleration- time relationship for a vehicle subjected to non- uniform acceleration is dvdt=(α−βv0)e−βt Where, v is the speed in m/s, t is the time in s, α and β are parameters, and v0 is the initial speed in m/s. If the accelerating behaviour of a vehicle, whose driver intends to overtake a slow moving vehicle ahead, is described as, dvdt=(α−βv) Considering α=2m/s2,β=0.05s−1 and dvdt=1.3 m/s2 at t=3s, the distance (in m) travelled by the vehicle in 35 sec is