Question

$T{i}^{3+}\left(aq\right)$ is purple while $T{i}^{4+}\left(aq\right)$ is colourless because:

• A. there is no crystal field effect in $T{i}^{4-}$
• B. there energy difference between $t_{2g}$ and $e_g$ of Ti^{4-}$ is quite high and does not fall in the visible region
• C. $T{i}^{4-}$ has $d^0$ configuration.
• D. $T{i}^{4-}$ is very stabilization energy for $[Co{F}_6{]}^{3-}$ in terms of parameter Dq is - $(\Delta =100Dq)$

Answer 1

The correct option is C $T{i}^{4-}$ has $d^0$ configuration.

$T{i}_{\left(aq\right)}^{3+}$ is purple while $T{i}_{\left(aq\right)}^{4+}$ is colourless because -

$T{i}^{4+}$ has $d^0$ configuration due to which d-d transition is not possible.$T{i}^{3+}$ has $d^1$configuration due to which d-d transition is possible. This results in purple colour.