Question

$T{i}^{3+}$ (aq.) is purple while $T{i}^{4+}$ (aq.) is colourless because :

• A. there is no crystal field effect in $T{i}^{4+}$
• B. the energy difference between $t_{2g}$ and $e_{g}T{i}^{4+}$ is quite high and does not fall in the visible region
• C. $T{i}^{4+}$ had $d^0$ configuration
• D. $T{i}^{4+}$ is very small in comparison to $T{i}^{3+}$ and hence does not absorb any radiation

Answer 1

Answer: (C)

$T{i}^{4+}$ had $d^0$ configuration

The outer electronic configuration of $T{i}^{3+}$ is $3d^1$. It contains one unpaired electron and is purple in color.
The outer electronic configuration of $T{i}^{4+}$ is $3d^0$. It contains no unpaired electron and is colorless.

Hence, option C is correct.