Question

$T{i}^{3+}$ is more easily reduced than $C{o}^{3+}$.

If true enter 1, else enter 0.

Answer 1

$T{i}^{3+}$ is more easily oxidised than $N{i}^{2+}$.

$T{i}^{3+}$ is strongly reducing agent in nature.

The electronic configuration of $T{i}^{3+}\to 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^1$.

It has a $d^1$ configuration. While acting as a reducing agent, it gets oxidized to $T{i}^{4+}$ (electronic configuration, $d^0$). This configuration is a more stable inert gas configuration.

$C{o}^{3+}$ is an oxidizing agent.

A common oxidation state of $Co$ for simple compounds is $+2$.

The electronic configuration of$C{o}^{3+}\to 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^6$.

It tends to accept two electrons and get reduced to achieve $d^7$ configuration which is a more stable configuration because the repulsion between the electrons of the two electron-pairs is less than for Co where there are 3 electron-pairs.