Question

Tick (✓) the correct answer
$\left(\frac{8}{-15}+\frac{4}{-3}\right)=?$
(a) $\frac{28}{15}$
(b) $\frac{-28}{15}$
(c) $\frac{-4}{5}$
(d) $\frac{-4}{15}$

Answer 1

(b) $\frac{-28}{15}$
$\frac{8}{-15}=\frac{-8}{15}$ and$\frac{4}{-3}=\frac{-4}{3}$

Now, we have:

$\left(\frac{8}{-15}+\frac{4}{-3}\right)=\left(\frac{-8}{15}+\frac{-4}{3}\right)$

LCM of 15 and 3 is $\left(3\times 5\times 1\right),\mathrm{that}\mathrm{is},15$

$\frac{-8}{15}+\frac{-4}{3}=\frac{1\times \left(-8\right)+5\times \left(-4\right)}{15}$
$$\begin{gathered} =\frac{\left(-8\right)+\left(-20\right)}{15} \\ =\frac{-28}{15} \end{gathered}$$