Tick the correct answer-a2-b c-a b-a c-a a-ba-cb a-bb-cc b-cc-ad aa-b-c

(a) (a + b)(a + c) a2+bc #160;+ab #160;+ac=a2+ab+bc #160;+ac=a(a+b)+c(a+b)=(a+c)(a+b) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Laws of Exponents

Tick the cor...

Question

Tick (✓) the correct answer:
a² + bc + ab + ac = ?
(a) (a + b)(a + c)
(b) (a + b)(b + c)
(c) (b + c)(c + a)
(d) a(a + b + c)

Open in App

Solution

(a) (a + b)(a + c)

$a^{2} + b c + a b + a c = a^{2} + a b + b c + a c = a (a + b) + c (a + b) = (a + c) (a + b)$

Suggest Corrections

Similar questions

$a^{2} + b c + a b + a c = ? (a) (a + b) (a + c) (b) (a + b) (b + c) (c) (b + c) (c + a) (d) a (a + b + c)$

Q. Prove that :

|\begin{matrix} a & b - c & c - b \\ a - c & b & c - a \\ a - b & b - a & c \end{matrix}| = (a + b - c) (b + c - a) (c + a - b)

The determinant
$∣ ∣ ∣ ∣ ∣ \begin{matrix} b^{2} - a b & b - c & b c - a c a b - a^{2} & a - b & b^{2} - a b b c - a c & c - a & a b - a^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣$ equals to:

(a) abc(b-c)(c-a)(a-b)
(b) (b-c)(c-a)(a-b)
(c) (a+b+c)(b-c)(c-a)(a-b)
(d) None of these

Q. Show that the expressions

a (a - b) (a - c) + b (b - c) (b - a) + c (c - a) (c - b)

and

a^{2} (a - b) (a - c) + b^{2} (b - c) (b - a) + c^{2} (c - a) (c - b)

are both positive.

∣ ∣ ∣ ∣ \begin{matrix} a + b & b + c & c + a b + c & c + a & a + b c + a & a + b & b + c \end{matrix} ∣ ∣ ∣ ∣ = K ∣ ∣ ∣ ∣ \begin{matrix} a & b & c b & c & a c & a & b \end{matrix} ∣ ∣ ∣ ∣

, then

K =

Join BYJU'S Learning Program

Tick (✓) the correct answer: a2 + bc + ab + ac = ? (a) (a + b)(a + c) (b) (a + b)(b + c) (c) (b + c)(c + a) (d) a(a + b + c)

(a) (a + b)(a + c) a2+bc +ab +ac=a2+ab+bc +ac=a(a+b)+c(a+b)=(a+c)(a+b)

Tick (✓) the correct answer:
a² + bc + ab + ac = ?
(a) (a + b)(a + c)
(b) (a + b)(b + c)
(c) (b + c)(c + a)
(d) a(a + b + c)

(a) (a + b)(a + c)

$a^{2} + b c + a b + a c = a^{2} + a b + b c + a c = a (a + b) + c (a + b) = (a + c) (a + b)$