Tick (✓) the correct answer:
ab − a − b + 1 = ?
(a) (a − 1)(b − 1)
(b) (1 − a)(1 − b)
(c) (a − 1)(1 − b)
(d) (1 − a)(b − 1)

Open in App

Solution

(a) (a − 1)(b − 1)

$a b - a - b + 1 = a (b - 1) - 1 (b - 1) = (a - 1) (b - 1)$

Suggest Corrections

Similar questions

$a b - a - b + 1 = ? (a) (a - 1) (b - 1) (b) (1 - a) (1 - b) (c) (a - 1) (1 - b) (d) (1 - a) (b - 1)$

[A (A + B)^{- 1} B]^{- 1} = B^{- 1} + A^{- 1}

[A (A + B)^{- 1} B]^{- 1} = [A (A^{- 1} + B^{- 1}) B]^{- 1} = [(I + A B^{- 1}) B]^{- 1} = [(B + A B^{- 1} B)]^{- 1} = [(B + A I)]^{- 1} = [(B + 1)]^{- 1} = B^{- 1} + A^{- 1}

Evaluate tan^-1(a - b)/(1+ab)+ tan^-1(b - c)/(1+bc)+ tan^-1(c - a)/(1+cb) ; ab,bc,ac>-1

tan [t a n^{- 1} (\frac{1}{a + b}) + t a n^{- 1} (\frac{b}{a^{2} + a b + 1})] =

Join BYJU'S Learning Program