Tick (✓) the correct answer:
ab − mn + an − bm = ?
(a) (a − b)(m − n)
(b) (a − m)(b + n)
(c) (a − n)(m + b)
(d) (m − a)(n − b)

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Solution

(b) (a − m)(b + n)

$a b - m n + a n - b m = a b + a n - m n - b m = a (b + n) - m (n + b) = (a - m) (b + n)$

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Similar questions

$a b - m n + a n - b m = ? (a) (a - b) (m - n) (b) (a - m) (b + n) (c) (a - n) (m + b) (d) (m - a) (n - b)$

Q. If

a

and

b

are non-zero integers,

m

and

n

are any integers, then which of the following are true?

Question 20

For non-zero numbers $a$ and $b$ , ${(\frac{a}{b})}^{m} \div {(\frac{a}{b})}^{n},$ where $m > n,$ is equal to:
(a) ${(\frac{a}{b})}^{m n}$
(b) ${(\frac{a}{b})}^{m + n}$
(c) ${(\frac{a}{b})}^{m - n}$
(d) ${({(\frac{a}{b})}^{m})}^{n}$

Q. In

△ A B C

, seg

M N ∥ s e g B C

, If

B M = 6, A N = 5, A M = 2

then find

N C

Q. Tick (✓) the correct answer:
ab − a − b + 1 = ?
(a) (a − 1)(b − 1)
(b) (1 − a)(1 − b)
(c) (a − 1)(1 − b)
(d) (1 − a)(b − 1)

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Tick (✓) the correct answer: ab − mn + an − bm = ? (a) (a − b)(m − n) (b) (a − m)(b + n) (c) (a − n)(m + b) (d) (m − a)(n − b)

(b) (a − m)(b + n) ab-mn+an-bm=ab+an-mn-bm=a(b+n)-m(n+b)=(a-m)(b+n)

Tick (✓) the correct answer:
ab − mn + an − bm = ?
(a) (a − b)(m − n)
(b) (a − m)(b + n)
(c) (a − n)(m + b)
(d) (m − a)(n − b)

(b) (a − m)(b + n)

$a b - m n + a n - b m = a b + a n - m n - b m = a (b + n) - m (n + b) = (a - m) (b + n)$