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Question

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If 64y8 is exactly divisible by 3, then the least value of y is
(a) 0
(b) 1
(c) 2
(d) 3

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Solution

(a) 0

If a number is divisible by 3, then the sum of the digits is also divisible by 3.
6+4+y+8=18+y
This is divisible by 3 as y is equal to 0.

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