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Lines of Symmetry for Regular Polygons

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Question

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In ∆ABC, AB = AC and AD ⊥ BC, BE ⊥ AC and CF ⊥ AB. Then ∆ABC is symmetrical about

(a) AD
(b) BE
(c) CF
(d) none of these

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Solution

(a) AD

This triangle is symmetrical only about AD.
Any isosceles triangle is symmetrical about its one altitude, which is drawn from the vertex between the two equal sides to the unequal side of the triangle.

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