Tick the correct answer:
In triangle $△ A B C$ :

$A B + B C = A C$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$A B + A C = B C$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$A B > B C + A C$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$A B + B C > A C$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
$A B + B C > A C$

A triangle is closed figure formed by joining three line segments, such that sum of any two sides is always greater than the third side.
So, in triangle $△ A B C$ , there are three sides $A B, B C, C A$ .
$A B + B C > A C$
Therefore, option(D) is the correct answer.

Suggest Corrections

Similar questions

Tick the correct answer and justify: In ΔABC, AB = cm, AC = 12 cm and BC = 6 cm.

The angle B is:

(A) 120° (B) 60°

{(\frac{- 3}{4})}^{2} = ?

\frac{- 9}{16}

\frac{9}{16}

\frac{16}{9}

\frac{- 16}{9}

{(\frac{- 1}{2})}^{3} = ?

\frac{- 1}{6}

\frac{1}{6}

\frac{1}{8}

\frac{- 1}{8}

{(\frac{2}{3})}^{0} = ?

\frac{3}{2}

\frac{2}{3}

Join BYJU'S Learning Program