Tick the correct answer-p q2-qp-1-1-a p q-1q-1b pq-1q-1c qp-1q-1d p q-1q-1

(d) (pq minus; 1) (q + 1) pq2+q(p 1) 1=pq2+qp q 1=pq(q+1) 1(q+1)=(pq 1)(q+1) ...

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Expansion of (x^2 - y^2)

Tick the cor...

Question

Tick (✓) the correct answer:
pq² + q(p − 1) − 1 = ?
(a) (pq + 1)(q − 1)
(b) p(q + 1)(q − 1)
(c) q(p − 1)(q + 1)
(d) (pq − 1) (q + 1)

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$p q^{2} + q (p - 1) - 1 = ? (a) (p q + 1) (q - 1) (b) p (q + 1) (p - 1) (c) q (p - 1) (q + 1) (d) (p q - 1) (q + 1)$

P = (1, 0, - 1) Q = (- 1, 2, 0) R = (2, 0, - 3) S = (3, - 2, - 1)

R S

P Q

A . P .,

p^{t h}

\frac{1}{q}

q^{t h}

\frac{1}{p},

p q

\frac{1}{2} (p q + 1),

p \neq q

If $p > q > 0 a n d p r < - 1 < q r$ , then find the value of

{tan}^{- 1} \frac{p - q}{1 + p q} + {tan}^{- 1} \frac{q - r}{1 + q r} + {tan}^{- 1} \frac{r - p}{1 + r p} .

= \int e^{a x} c o s b x d x

= \int e^{a x} s i n b x d x

t a n^{- 1} (\frac{Q}{P}) + t a n^{- 1} (\frac{b}{a}) =

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