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Question

Tick (✓) the correct answer:
The angles of a pentagon are x°, (x + 20)°, (x + 40)°, (x + 60)° and (x + 80)°. The smallest angle of the pentagon is
(a) 75°
(b) 68°
(c) 78°
(d) 85°

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Solution

(b) 68°
​Sum of all the interior angles of a polygon with n sides = n-2×180°

(5-2)×180o=x+x+20+x+40+x+60+x+80 540 = 5x + 200 5x = 340 x = 68o

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