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Three cubes of iron whose edges are 6 cm, 8 cm and 10 cm respectively are melted and formed into a single cube. The edge of the new cube formed is
(a) 12 cm
(b) 14 cm
(c) 16 cm
(d) 18 cm

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Solution

(a) 12 cm

Total volume $= 6^{3} + 8^{3} + 10^{3} = 216 + 512 + 1000 = 1728 c m^{3}$
∴ Edge of the new cube $= \sqrt[3]{1728} = 12 c m$

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Tick (✓) the correct answer: Three cubes of iron whose edges are 6 cm, 8 cm and 10 cm respectively are melted and formed into a single cube. The edge of the new cube formed is (a) 12 cm (b) 14 cm (c) 16 cm (d) 18 cm

(a) 12 cm Total volume =63+83+103=216+512+1000=1728 cm3 ∴ Edge of the new cube=17283=12 cm

Tick (✓) the correct answer:
Three cubes of iron whose edges are 6 cm, 8 cm and 10 cm respectively are melted and formed into a single cube. The edge of the new cube formed is
(a) 12 cm
(b) 14 cm
(c) 16 cm
(d) 18 cm

(a) 12 cm

Total volume $= 6^{3} + 8^{3} + 10^{3} = 216 + 512 + 1000 = 1728 c m^{3}$
∴ Edge of the new cube $= \sqrt[3]{1728} = 12 c m$