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Two adjacent angles of a parallelogram are (2x + 25)° and (3x − 5)°. The value of x is
(a) 28
(b) 32
(c) 36
(d) 42

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Solution

$(b) 32 We know that the sum of adjacent angles of a parallelogram i s 180 ° . \Rightarrow 2 x + 25 + 3 x - 5 = 180 \Rightarrow 5 x + 20 = 180 \Rightarrow 5 x = 180 - 20 \Rightarrow 5 x = 160 \Rightarrow x = \frac{160}{5} \Rightarrow x = 32 Therefore, the value of x is 32 .$

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Tick (✓) the correct answer Two adjacent angles of a parallelogram are (2x + 25)° and (3x − 5)°. The value of x is (a) 28 (b) 32 (c) 36 (d) 42

(b) 32We know that the sum of adjacent angles of a parallelogram is180°.⇒2x+25+3x-5=180⇒5x+20=180⇒5x=180-20⇒5x=160⇒x=1605⇒x=32Therefore, the value of x is 32.

Tick (✓) the correct answer
Two adjacent angles of a parallelogram are (2x + 25)° and (3x − 5)°. The value of x is
(a) 28
(b) 32
(c) 36
(d) 42

$(b) 32 We know that the sum of adjacent angles of a parallelogram i s 180 ° . \Rightarrow 2 x + 25 + 3 x - 5 = 180 \Rightarrow 5 x + 20 = 180 \Rightarrow 5 x = 180 - 20 \Rightarrow 5 x = 160 \Rightarrow x = \frac{160}{5} \Rightarrow x = 32 Therefore, the value of x is 32 .$