Tick the correct answer-x2-6 x-8-a x-3x-5b x-3x-4c x-2x-4d x-1x-8

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Addition of Negative Numbers

Tick the cor...

Question

Tick (✓) the correct answer:
x² + 6x + 8 = ?
(a) (x + 3)(x + 5)
(b) (x + 3)(x + 4)
(c) (x + 2)(x + 4)
(d) (x + 1)(x + 8)

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Solution

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Factorize: $x^{2} + 6 x + 8 = ? (a) (x + 3) (x + 5) (b) (x + 3) (x + 4) (c) (x + 2) (x + 4) (d) (x + 1) (x + 8)$

\sqrt{3} x^{2} - 2 x + \frac{1}{2} = 0

x^{2} + \frac{1}{x^{2}} = 5

x - \frac{3}{x} = x^{2}

2 x^{2} - \sqrt{3 x} + 9 = 0

x^{2} - 2 x - \sqrt{x} - 5 = 0

x + \frac{1}{x} = 1

{(x + \frac{1}{x})}^{2} = 3 (x + \frac{1}{x}) + 4

x + \frac{1}{x} = x^{2}, x \neq 0

Factorize: $x^{2} - 7 x + 12$

Factorise by splitting the middle term 2x² – 11x + 12

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