Tickets are numbered 1 to 10. Two tickets are drawn one after the other at random with replacement. Find the probability that the number on one of the ticket is a multiple of 5 and the other is a multiple of 4.
A
1/25
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B
2/25
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C
3/25
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D
4/25
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Solution
The correct option is A2/25
Probability = Favorable outcome / Total Outcome
Total Outcomes = 10×10=100 (there will be 10 possibilities each time 'With replacement')
A favourable outcome will be obtained when one of the tickets is a multiple of 5 and the other is a multiple of 4. There are 2 multiple of 5 and 2 multiple of 4 for selection of ball.