Tickets are numbered from $1$ to $20$ and $1$ ticket is picked at random. What is the probability that the ticket drawn at random is a multiple of $3$ or $5$ .

\frac{1}{2}

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\frac{2}{5}

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\frac{8}{15}

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\frac{9}{20}

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Solution

The correct option is D $\frac{9}{20}$
Total tickets $= 20$ (Numbered from $1$ to $20$ )
One ticket drawn having multiple of $3$ or $5$ are: $E = {3, 6, 9, 12, 15, 18, 5, 10, 20}$
Probability: $P (E) = \frac{9}{20}$

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Tickets are numbered from 1 to 20 and 1 ticket is picked at random. What is the probability that the ticket drawn at random is a multiple of 3 or 5.

The correct option is D 920Total tickets =20 (Numbered from 1 to 20)One ticket drawn having multiple of 3 or 5 are: E={3,6,9,12,15,18,5,10,20}Probability: P(E)=920

Tickets are numbered from $1$ to $20$ and $1$ ticket is picked at random. What is the probability that the ticket drawn at random is a multiple of $3$ or $5$ .

The correct option is D $\frac{9}{20}$
Total tickets $= 20$ (Numbered from $1$ to $20$ )
One ticket drawn having multiple of $3$ or $5$ are: $E = {3, 6, 9, 12, 15, 18, 5, 10, 20}$
Probability: $P (E) = \frac{9}{20}$