Question

Tickets numbered from 1 to 20 are mixed up and a ticket is drawn at random What is the probability that the ticket drawn has a number which is a multiple of 3 or 7 ?

• A. $\frac{1}{15}$
• B. $\frac{1}{2}$
• C. $\frac{2}{5}$
• D. $\frac{7}{20}$

Answer 1

The correct option is C $\frac{2}{5}$

Since, total tickets = $20$
Multiples of 3 or 7 from 1 to 20 are:
$3,6,7,9,12,14,15,18$
$\therefore$ favorable outcomes=$8$
$\therefore$ required probability = $\frac{8}{20}=\frac{2}{5}$
$\therefore$ Option C is correct.