Out of 20 tickets numbered from 1 to 20, one can be chosen in 20m ways. So, total number of elementary events associated with the given random experiment is 20. Out of 20 tickets numbered 1 to 20, tickets bearing numbers which are multiple of 3 or 7 bear numbers 3,6,7,9,12,14,15 and 18.
Favourable number of elementary events = 8
Hence, required probability = 820 = 25