$T i C l_{4}$ is reduced to $T i C l_{3}$ which is violet in colour. Which of the following cannot facilitate this reduction?

S O_{2}

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Solution

The correct option is A $S O_{2}$
$Z n, S n$ and $C d$ are metals so they can undergo oxidation easily and can act as reducing agents. $S O_{3}$ can't reduce $T i C l_{4}$ to $T i C l_{3}$ as $S$ is already in its highest oxidation state.

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