$T i I_{4}$ on heating gives

T i I_{2} + I_{2}

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T i + 2 I_{2}

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T i I_{3} + \frac{1}{2} I_{2}

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None of these

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Solution

The correct option is B $T i + 2 I_{2}$
$T i I_{4}$ on heating gives titanium and iodine. It is the van Arkel method for the production of pure Ti.
$T i I_{4} H e a t - -- \to T i + 2 I_{4}$

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Similar questions

Find the conjuagates of the following complex numbers :

$(i) 4 - 5 i (i i) \frac{1}{3 + 5 i} (i i i) \frac{1}{1 + i} (i v) \frac{(3 - i)^{2}}{2 + i} (v) \frac{(1 + i) (2 + i)}{3 + i} (v i) \frac{(3 - 2 i) (2 + 3 i)}{(1 + 2 i) (2 - i)}$

Q. Find the conjugates of the following complex numbers:
(i) 4 − 5 i
(ii)

\frac{1}{3 + 5 i}

(iii)

\frac{1}{1 + i}

(iv)

\frac{(3 - i)^{2}}{2 + i}

(v)

\frac{(1 + i) (2 + i)}{3 + i}

(vi)

\frac{(3 - 2 i) (2 + 3 i)}{(1 + 2 i) (2 - i)}

\frac{(3 - 2 i) (2 + 3 i)}{(1 + 2 i) (2 - i)} =

Q. Find the conjugate of

\frac{(3 - 2 i) (2 + 3 i)}{(1 + 2 i) (2 - i)}

Q. Evaluate and write in standard form:

{(- 3 + 2 i)}^{2} - 3 (3 - i) (- 2 + 2 i)

, where

i^{2} = - 1

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TiI4 on heating gives

The correct option is B Ti+2I2TiI4 on heating gives titanium and iodine. It is the van Arkel method for the production of pure Ti.TiI4Heat−−−→Ti+2I4

$T i I_{4}$ on heating gives

The correct option is B $T i + 2 I_{2}$
$T i I_{4}$ on heating gives titanium and iodine. It is the van Arkel method for the production of pure Ti.
$T i I_{4} H e a t - -- \to T i + 2 I_{4}$