Time 0 5min 10min 15min -A- 20mol 18mol 16mol 16 molFor the reaction A- Products- -d-A- - dt -k and at different time interval- IAI values are given- At 20 minute- rate will be -

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Time 0 5min 1...

Question

Time 0 5min 10min 15min
[A] 20mol 18mol 16mol 16 mol
For the reaction $A ⟶ P r o d u c t s$ ; $\frac{- d [A]}{d t} = k$ and at different time interval, IAI values are given. At $20$ minute, rate will be :

12 m o l / m i n

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10 m o l / m i n

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8 m o l / m i n

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0.4 m o l / m i n

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A ⟶ p r o d u c t, - \frac{d [A]}{d t} = k

Time	0	5 min	10 min	15 min
$[A]$	$20 m o l$	$18 m o l$	$16 m o l$	$14 m o l$

A \to

- \frac{d [A]}{d t} = k

[A]

Time	0	5 min	10 min	15 min
[A]	20 mol	18 mol	16 mol	14 mol

A \to P r o d u c t s

10 m o l e / l i t / m i n

t_{1}) = 2 m i n s

m o l / l i t / m i n

t_{2}) = 12 m i n s

\to

%

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}, \frac{d [N O_{2}]}{d t}

2.4 \times 10^{- 4} m o l e L^{- 1} m i n^{- 1}

4.4 \times 10^{- 4} m i n^{- 1}

- \frac{d [N_{2} O_{5}]}{d t}

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