You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Physics

Charging of Capacitors

Time constant...

Question

Time constant of a capacitor and capacitance are 5s and $100 n F$ . It is charged from zero by a cell of emf $10 V$ through a resistor. The charge on it after 3 s is.

4.5 \times 10^{- 6} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9 \times 10^{- 6} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.5 \times 10^{- 7} C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

9 \times 10^{- 7} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $4.5 \times 10^{- 7} C$
Use the equation,
$q = C E (1 - e^{- \frac{t}{R C}})$
We know that time constant, $τ = R C = 5 s$
So,
At t=3 sec,
$q = 100 \times 10^{- 9} \times 10 (1 - e^{- \frac{3}{5}})$
$q = 10^{- 6} (0.451)$
$q = 4.51 \times 10^{- 7} C$

Suggest Corrections

Similar questions

Q. The time constant of a capacitor is 5sec. If the capacitance is C=100nF and it is charged from zero by a cell of EMF 10V through a resistor. What is the charge on it after 3 seconds?

Q. A capacitor of capacitance C is given a charge

q_{o}

. At time

t = 0

, it is connected to a battery of emf E through a resistance R. Find the charge on the capacitor at time t.

A capacitor of $10 μ F$ capacitance is charged by a $12 V$ battery. Now the space between the plates of capacitors is filled with a dielectric of dielectric constant $K = 3$ and again it is charged. The magnitude of the charge is :

Q. A capacitor of capacitance 500 μF is connected to a battery through a 10 kΩ resistor. The charge stored in the capacitor in the first 5 s is larger than the charge stored in the next.
(a) 5 s
(b) 50 s
(c) 500 s
(d) 500 s

Q. A Circuit contains a resistor of resistance

R

and a capacitor

C_{1}

of capacitance

C

, a second Capacitor

C_{2}

of capacitance

2 C

, and a battery that provides an emf of

V

, as shown above. Initially both switches are open and both capacitors are uncharged. At time t=0, Both switches are closed. After the circuit reaches steady state, what is the charge

Q_{2}

on capacitor

C_{2}

Join BYJU'S Learning Program

Time constant of a capacitor and capacitance are 5s and 100 nF. It is charged from zero by a cell of emf 10 V through a resistor. The charge on it after 3 s is.

The correct option is C 4.5×10−7CUse the equation, q=CE(1−e−tRC) We know that time constant, τ=RC=5 s So, At t=3 sec, q=100×10−9×10(1−e−35) q=10−6(0.451) q=4.51×10−7C

Time constant of a capacitor and capacitance are 5s and $100 n F$ . It is charged from zero by a cell of emf $10 V$ through a resistor. The charge on it after 3 s is.

The correct option is C $4.5 \times 10^{- 7} C$
Use the equation,
$q = C E (1 - e^{- \frac{t}{R C}})$
We know that time constant, $τ = R C = 5 s$
So,
At t=3 sec,
$q = 100 \times 10^{- 9} \times 10 (1 - e^{- \frac{3}{5}})$
$q = 10^{- 6} (0.451)$
$q = 4.51 \times 10^{- 7} C$