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Byju's Answer

Standard XII

Physics

Charging of Capacitors

Time constant...

Question

Time constant of an R-C circuit is that time, in which on closing the circuit the value of charge $q$ on condenser plates becomes (where $q_{0}$ is maximum charge on capacitor)

0.37 q_{0}

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0.636 q_{0}

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0.5 q_{0}

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q_{0}

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Solution

The correct option is B $0.636 q_{0}$
We define product $R C$ as time constant of $R C$ circuit.
The equation in case of charging is
$q = q_{o} ⎛ ⎜ ⎝ 1 - e^{\frac{- t}{R C}} ⎞ ⎟ ⎠$
Now when our $t = R C$
our equation becomes $q = q_{o} (1 - e^{-} 1)$
which gives $q = 0.636 q_{o}$

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Time constant of an R-C circuit is that time, in which on closing the circuit the value of charge q on condenser plates becomes (where q0 is maximum charge on capacitor)

The correct option is B 0.636q0We define product RC as time constant of RC circuit.The equation in case of charging isq=qo⎛⎜⎝1−e−tRC⎞⎟⎠Now when our t=RCour equation becomes q=qo(1−e−1)which gives q=0.636qo

Time constant of an R-C circuit is that time, in which on closing the circuit the value of charge $q$ on condenser plates becomes (where $q_{0}$ is maximum charge on capacitor)

The correct option is B $0.636 q_{0}$
We define product $R C$ as time constant of $R C$ circuit.
The equation in case of charging is
$q = q_{o} ⎛ ⎜ ⎝ 1 - e^{\frac{- t}{R C}} ⎞ ⎟ ⎠$
Now when our $t = R C$
our equation becomes $q = q_{o} (1 - e^{-} 1)$
which gives $q = 0.636 q_{o}$