Time required for coffee to have 105∘F temperature is
A
6 min
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B
6.43 min
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C
7.23 min
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D
7.63 min
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Solution
The correct option is D7.63 min dTdt=−k(T−t),k>0 Integrating to get T−To=(Ti−To)e−kt given Ti=185 To=65 If in two minutes T=155 90=120e−2k k=0.1438min−1 . Time required for 105o is 40=120e−0.1438t t=7.63min