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Standard XII

Chemistry

Faraday's Second Law

Time required...

Question

Time required to produce 1 kg of $C l_{2}$ in hrs is $(40 + x)$ . Find value of $x$ (nearest integer value).

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Solution

Now $m = \frac{E . i . t}{96500}$

$∴ m_{{C l}_{2}} = 10^{3} g = 35.5$

$i = \frac{(25 \times 62)}{100 A}$

$∴$ $10^{3} = \frac{35.5 \times 25 \times 62 \times t}{100 \times 96500}$

$∴$ t = 175374.83 second = 48.71 hours
So nearest integer for $x$ will be 9.

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Time required to produce 1 kg of Cl2 in hrs is (40+x). Find value of x (nearest integer value).

Now m=E.i.t96500∴mCl2=103 g=35.5i=(25×62)100A∴ 103=35.5×25×62×t100×96500∴ t = 175374.83 second = 48.71 hours So nearest integer for x will be 9.

Time required to produce 1 kg of $C l_{2}$ in hrs is $(40 + x)$ . Find value of $x$ (nearest integer value).

Now $m = \frac{E . i . t}{96500}$

$∴ m_{{C l}_{2}} = 10^{3} g = 35.5$

$i = \frac{(25 \times 62)}{100 A}$

$∴$ $10^{3} = \frac{35.5 \times 25 \times 62 \times t}{100 \times 96500}$

$∴$ t = 175374.83 second = 48.71 hours
So nearest integer for $x$ will be 9.