Time taken by the projectile to reach from A to B is t. Then, the distance AB is equal to
A
ut√3
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B
√3ut2
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C
√3ut
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D
2ut
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Solution
The correct option is Aut√3
Angle of projection with the horizontal =60∘
Horizontal distance covered in time t =ucos60∘×t=ABcos30∘ (by geometry) ∴AB=ut√3