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Question
Tina has 12 pink marbles and 15 green marbles. If she wants to put them in identical bags such that each bag has only one kind of marble, what is the maximum number of marbles each bag can have?
Tina has 12 pink marbles and 15 green marbles. If she wants to put them in identical bags such that each bag has only one kind of marble, what is the maximum number of marbles each bag can have?
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Solution
The correct option is D 3
To solve this problem, first we have to break down both the numbers into prime factors.
The prime factorization of 12 is: 2 × 2 × 3
The prime factorization of 15 is: 3 × 5
Thus, the greatest common divisor is 3.
Hence, each bag will have 3 marbles.
Additionally,
Number of bags with pink marbles: 12 ÷ 3 = 4
Number of bags with green marbles: 15 ÷ 3 = 5
To solve this problem, first we have to break down both the numbers into prime factors.
The prime factorization of 12 is: 2 × 2 × 3
The prime factorization of 15 is: 3 × 5
Thus, the greatest common divisor is 3.
Hence, each bag will have 3 marbles.
Additionally,
Number of bags with pink marbles: 12 ÷ 3 = 4
Number of bags with green marbles: 15 ÷ 3 = 5
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