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Question

To 20 mL of 1.5 M HCl solution, 30 mL of water is added and to this resultant solution again 75 mL of 0.4 M HCl is added. The molarity of the resultant solution is:

A
0.40 M
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B
2.10 M
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C
0.56 M
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D
5.5 M
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Solution

The correct option is C 0.56 M
In the first case,
M1V1=M2V2
here, M1=1.5 M;V1=20 mL;V2=50 mL
So M2=1.5×2050=0.6 M
Now, to this 0.6 M of 50 mL HCl solution, 75 mL of 0.4 M HCl is added.
Using,
M3=M1V1+M2V2V3
where V3=50+75=125 mL
M3=(0.6×50)+(75×0.4)125M3=0.56 M

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