To 50 g of water at 00 C is added 20 g of ice at 00 C- What will be the mass of water that will freeze or ice that will melt-A- 20 g of water freezesB- 30 g of water freezesC- 20 g of ice will meltD- No ice will melt - nor will any water freezeE- 30 g of ice will melt

10 g of ice at $- 20^{\circ} C$ is dropped into a calorimeter containing 10 g of water at $10^{\circ} C$ ; the specific heat of water is twice that of ice. Ehen equilibrium is reached, the calorimeter will contain

30 g

of ice at

0^{0} C

and

20 g

of steam at

100^{0} C

are mixed. The composition of the resultant mixture is:

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To 50 g of water at 00C is added 20 g of ice at 00C. What will be the mass of water that will freeze or ice that will melt?

The correct option is E No ice will melt ; nor will any water freezeSince ice and water are bot at 0oC, it is a state of Thermal Equilibrium, and therefore no heat will be exchanged between them. Thus no ice will melt, nor will any water freeze.

To 50 g of water at 0⁰C is added 20 g of ice at 0⁰C. What will be the mass of water that will freeze or ice that will melt?

The correct option is E
No ice will melt ; nor will any water freeze

Since ice and water are bot at 0^oC, it is a state of Thermal Equilibrium, and therefore no heat will be exchanged between them. Thus no ice will melt, nor will any water freeze.