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Ideal Gas Law

To a 25 mL ...

Question

To a $25$ mL $H_{2} O_{2}$ solution, excess of an acidified solution of potassium iodide was added. The iodine liberated required $20$ mL of $0.3$ N sodium thiosulphate solution.

Calculate the volume strength of $H_{2} O_{2}$ solution (to the nearest integer):

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Solution

Milliequivalents of $N a_{2} S_{2} O_{3} = 20 \times 0.3 = 6$

Milliequivalents of $I_{2} = 6$

Milliequivalents of $K I = 6$

Milliequivalents of $H_{2} O_{2} = 6$

Normality of $H_{2} O_{2} = \frac{6}{25}$

For $H_{2} O_{2}$ , $5.6 \times$ Normality $=$ Volume strength

$∴$ Volume strength $= \frac{6}{25} \times 5.6 = 1.344$
Hence, the answer is $1$ (to the nearest integer).

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