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Hydrogen Peroxide

To a 30 mL of...

Question

To a $30 m L$ of $H_{2} O_{2}$ solution, excess of acidified solution of $K I$ was added. The iodine liberated required $20 m L$ of $0.3 N N a_{2} S_{2} O_{3} .$ Calculate the volume stregnth of $H_{2} O_{2}$ solution.

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Solution

Miliequivalent of $30 m L H_{2} O_{2}$ = Miliequivalent of $I_{2}$ = Miliequivalent of $N a_{2} S_{2} O_{3}$ = $20 \times 0.3 = 6.$
Normality of $H_{2} O_{2} = \frac{6}{30} e q / L$
Let, the volume stregnth of $H_{2} O_{2}$ be $^{'} x V^{'} .$ Thus, $1 L$ of $H_{2} O_{2}$ produces $x L$ of $O_{2}$ .
Volume strength = 5.6 x Normality
= 5.6 (6/30) =1.12 volume
The volume stregnth of $H_{2} O_{2}$ is $1.12 V o l u m e$

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Hydrogen Peroxide

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