To break a wire of 1 m length, minimum 40 kg weight is required. Then the wire of the same material of double radius and 6 m length will require breaking weight
A
80 kg weight
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B
240 kg weight
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C
200 kg weight
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D
160 kg weight
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Solution
The correct option is D 160 kg weight Breaking stress is constant for the wire Stress =FAF1A1=F2A2⇒F2=F1(A2A1)=40(π(2r)2r2)F2=160kg−wt