Question

To complete a work $A$ takes $15\%$ more time than $B$. If together they take $18$ days to complete the work, how much time shall $B$ take to do it?

Answer 1

Suppose $B$ takes $x$ days.

Then, $A$ take = $\frac{15}{100}\times x=\frac{3x}{2}$ days

Therefore,

$\frac{1}{x}+\frac{2}{3x}=\frac{1}{18}$

$3x=90$

$x=30$

Hence, $B$ takes $30$ days.