Question

To construct a right triangle whose base is $12cm$ and sum of its hypotenuse and other side is $18cm$. We draw line segment $BC$ of $12cm$. Draw a ray $BX$ making ${90}^0$ with $AB$. The next step is:

• A. Cut a line segment $AD$ of $18$ cm on $AX$
• B. Cut a line segment $BD$ of $18$ cm on $BX$
• C. Cut a line segment $BD$ of $18$ cm on $AB$
• D. Cut a line segment $AD$ of $18$ cm on $AB$

Answer 1

Answer: (B)

Cut a line segment $BD$ of $18$ cm on $BX$

1. Draw base BC = 12cm and at point B make on $angle$ of ${90}^0$

2. Cut a line segment BD=AB + AC from ray BX

3. Join DC. Draw perpendicular bisector PQ of line DC

4. Let PQ intersect BD at point A.Join AC.