Question

To construct a trapezium ABCD with $AB\parallel CD,$ AB = 6.5 cm, BC = 6.2 cm, $\angle ABC={80}^{\circ }$ and $\angle DAB={105}^{\circ },$ we follow the following steps:
1) Draw the line segment AB = 6.5 cm.
2) Construct the angle $\angle ABX={80}^{\circ }$ at B.
3) With B as centre, draw an arc of radius 6.2 cm cutting BX at C.
4) Draw CD parallel to AB.
The next step involved in the construction is __.

• A. From the point A, draw an arc of radius 6.2 cm cutting CY.
• B. Construct the angle $\angle BAZ={105}^{\circ }$ at A cutting CY at D.
• C. From the point A, draw an arc of radius 6.6 cm cutting CY.
• D. Construct the angle $\angle BAZ={75}^{\circ }$ at A cutting CY at D.

Answer 1

The correct option is B Construct the angle $\angle BAZ={105}^{\circ }$ at A cutting CY at D.


The steps involved in the construction of the given trapezium ABCD is as follows:
1) Draw the line segment AB = 6.5 cm.
2) Construct the angle $\angle ABX={80}^{\circ }$ at B.
3) With B as centre, draw an arc of radius 6.2 cm cutting BX at C.
4) Draw CD parallel to AB.
5) Construct the angle $\angle BAZ={105}^{\circ }$ at A cutting CY at D.
Join ABCD. This is the required trapezium.