Question

To construct a triangle $ABC$ in which $\angle B={60}^{\circ },\angle C={45}^{\circ }$ and $AB+BC+AC=12cm$,

The steps of construction are:
Step 1: Draw a line segment XY = 12 cm.
Step 2: At X, construct an angle of ${60}^{\circ }$, and at Y construct an angle of ${45}^{\circ }$.
Step 3: Bisect these angles. Let the bisectors of these angles intersect at point A.
Step 4 will be

• A. Draw perpendicular bisector PQ of XA to intersect XY at B and RS of YA to intersect XY at C
• B. Draw perpendicular bisector PQ of XB to intersect XY at B and RS of YC to intersect XY at C
• C. Join AB and AC to obtain required $\Delta ABC$
• D. Bisect these angles.Let bisector of these angles intersect at point A

Answer 1

The correct option is A Draw perpendicular bisector PQ of XA to intersect XY at B and RS of YA to intersect XY at C

Step 4: Draw perpendicular bisectors PQ of XA to intersect XY at B and RS of YA to intersect XY at C.
Then join points A, B and C.
$\Delta ABC$ is the required triangle.